Aprofessor has noticed that students that attend class regularly, miss no more than two classes per term, generally get better grades. for the class, the overall percent of students who attend regularly is 84%. of those who come to class on a regular basis, 42% receive a's. of those who don't attend regularly, only 6% get a's. draw a tree diagram like the one in the image, where r = "attends class regularly", r' = "does not attend class regularly", a = "earned an a", a' = "did not earn an a". diagram for attendance that includes the first branches with regular attendance and secondary branches with a and not a grades (a) based on your tree diagram fill in the appropriate matching probabilities, enter your answer as a proportion with three decimal places.: a. or p(r) = .840 b. or p(r') = .160 c. or p(a|r) = .420 d. or p(a'|r) = .580 e. or p(a|r') = .060 f. or p(a'|r') = .940 (b)among all students what proportion earn an a and don't attend class regularly? .001 (c)what is the chance a randomly chosen student will earn an a in the class? hint: use the total law of probability. (d)given a student earned an a, what is the chance they attend class regularly? hint: p(r|a)

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.

b

step-by-step explanation:

1. sometimes

2.   never

3   .08c = 7.50+.05c   250 pages

step-by-step explanation:

1.   sometimes

the theoretical probability of rolling a 1 is 1/6.   perhaps you got really lucky and never rolled a 1   in those 60 times.   your experimental probability is 0.   or perhaps you rolled a 1   20 times.   your experimental probability is 20/60 is 1/3.     it really just depends on how you rolled in that experiment.

2.   never

the probability of the event occurring is 1.   that is being 100 % sure it will happen.   that is the maximum amount of confidence we have.

3.   no customer card cost:   .08 times number of pages

customer card cost:   7.50 + .05 times number of pages

we want to find when it costs the same amount, so we will set these equal

let c = number of pages

.08c = 7.50+.05c

subtract .05c from each side

.08c-.05c = 7.5+.05c-.05c

.03c=7.5

divide each side by .03

.03c/.03 = 7.5/03

c =250  

the cost is the same at 250 pages

he has 140 chickens because he has 10 times more chickens than ducks and he has 14 ducks so 14*10=140