Need asap 70 points given: △ace, bd¯¯¯¯¯∥ae¯¯¯¯¯ prove: ba/cb=de/cd drag an expression or phrase to each box to complete the proof.

Ayo, for anyone who needs it -

Step-by-step explanation:

Statement                                                                Reason

ΔACE, BD║AE                                                          Given

∠4≅∠1 and ∠3≅∠2                                      Corresponding angle postulate

ΔACE is similar to ΔBCD                             Angle-Angle similarity postulate

         Definition of similar triangles

CA=CB+BA and CE=CD+DE                        Segment addition postulate

Substitution property of equality.

Addition of fractions.

   Simplification of fractions

        Subtraction property of equality.

5/12, or 5: 12

step-by-step explanation:

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form