What is the product of (3p-7)(2p²-3p-4)a.6p³+23p²+9p+28b.6 p³-23p²-9p+28c.6p³-23p²+9p+28d.6p³+ 23p²-9p+28

Choice C is the correct answer.

Step-by-step explanation:

Given expression is

(3p-7)(2p²-3p-4)

we have to find the product of linear expression to quardatic expression.

Firstly, multiply 3p to quardatic expression and -7 to quardatic expression and add.

3p(2p²-3p-4)-7(2p²-3p-4)

Multiply 3p to each term of quardatic expression and -7 to each term of quardatic expression and add all terms:

3p(2p²)+3p(-3p)+3p(-4)-7(2p²)-7(-3p)-7(-4)

6p³-9p²-12p-14p²+21p+28

add like terms

6p³+(-9-14)p²+p(-12+21)+28

6p³-23p²+9p+28 which is the correct answer.

c.

step-by-step explanation:

because first you have to add the 4x, 9x, and the 7x together and you get 20x and then you add the last numbers up and you get 5and then you put the subtraction sign in there and that's how you get the answer.

where is the picture

step-by-step explanation: