From his home, bob would have to walk 3 miles north to get to his friend lucky’s house and 4 miles east to get to his friend raymond’s house. one day, bob walked from his home to raymond’s house. together, raymond and bob cut directly through the field that separated them from lucky’s house. when they finished playing at lucky’s, bob walked back home. in all how far did bob walk?

  12 miles

Step-by-step explanation:

The diagonal distance from Raymond's house to Lucky's house is given by the Pythagorean theorem as ...

  c = √(a² +b²) . . . . . where c is the hypotenuse length of a right triangle with legs "a" and "b"

Here, we have a=4, b=3, so ...

  c = √(4²+3²) = √(16+9) = √25 = 5 . . . . miles

So, Raymond's trip that day was ...

  distance to Raymond's + distance from Raymond's to Lucky's + distance from Lucky's

  = 4 + 5 + 3 = 12 . . . . miles

6.5

step-by-step explanation:

you said it was in the question

~courtney