If the feed per revolution on an upright drilling machine is set to 1/64" and the rpm is set to 105, how many revolutions are required for the drill to advance 2 1/8" into the part?

Proportion states that the two ratios or fractions are equal.

As per the given statement:

f the feed per revolution on an upright drilling machine is set to 1/64" and the rpm is set to 105.

Let x represents the revolutions are required  for the drill to advance into the part.

By definition of proportion:

By cross multiply we have;

Multiply both sides by 64 we get;

Simplify:

Therefore, 14,280 rpm revolutions are required for the drill to advance into the part

step-by-step explanation:

if you meant, "on the way from (3, 2) to (3, 14):

x does not change; y increases by 12.

ensure that you have copied down this problem correctly.   .

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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