State the quotient and remainder when the first polynomial is divided by the second. 3x^4-3x^3-11x^2+6x-1; x^3+x^2-2

, and . Subtracting this from the numerator leaves a remainder of

, and . Subtracting this from the previous remainder gives a new remainder of

has no factors of , so we stop here. Then

Q = 3x – 6; R = -5x² + 12x - 13

Step-by-step explanation:

One way is to use long division.

                 3x    - 6                                                

x³ + x² - 2) 3x⁴  - 3x³ - 11x² +    6x -  1

                 3x⁴ + 3x³           -    6x    

                       -  6x³ - 11x²  + 12x  -  1

                       -  6x³ - 6x²            + 12

                                 - 5x²  + 12x  - 13

Quotient = 3x – 6; Remainder = -5x²+ 12x - 13

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.

i can answer this question sweetie!

step-by-step explanation: