Find the equation of the axis of symmetry for the parabola y=x^2-6x+41/5

x = 3

Step-by-step explanation:

given a parabola in standard form : y = ax² + bx + c : a ≠ 0

Then the equation of the axis of symmetry is

x = -

y = x² - 6x + is in standard form

with a = 1 and b = - 6, hence

x = - = 3

equation of axis of symmetry is x = 3

make sure you have version 2.50

try looking in the very back of the book : )

step-by-step explanation:

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