Which graph represents the function over the interval [−3, 3] ? f(x)=⌈x+1⌉

We are asked to find which graph represent the function f(x)= over the interval [-3,3]

We know that the ceiling function has following properties:

" The ceiling function (also known as the least integer function) of a real number  x, denoted by is defined as the smallest integer that is not smaller than x ".

The graph of the function f(x) between [-3,3] is attached to the answer.

when x=-3 then f(x)= -2

The function will give the value between  -3<x≤-2  to be -1.

since when  -3<x≤-2 then -2<x+1≤ -1

Hence f(x)= -1

Similarly when -2<x≤-1 then f(x)=0

when -1<x≤0  then f(x)=1      

when 0<x≤1  then f(x)=2

when 1<x≤2  then f(x)=3

when 2<x≤3  then f(x)=4

The graph is attached to the answer.

step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.