Pls asa will mark brainliest the length of a rectangle is 1 ft less than three times the width. the area is 310 ft^2.find the dimensions of the rectangle

w = 10

l=31

Step-by-step explanation:

To calculate an area of a rectangle, use the formula A=l*w. We know the length is 1 ft less than three times the width. So l = 3w - 1. So the area is A= (3w-1)*w.

We also know the area is 310. Substitute this value for A and solve.

To solve the quadratic, use the quadratic formula:

Here a=3, b=-1 and c=-310.

This is w and must be positive since it is distance. So w=10.333....

To find l, substitute into l = 3w-1.

l=3(10.333..)-1

l=31-1 = 30

answer is 8x+24

area of vanessa's patio = length × width

given, length = (3x² + 5x + 10)

width = (x² - 3x - 1)

area of vanessa's patio = (3x² + 5x + 10)(x² - 3x - 1)

= 3x²(x² - 3x - 1) + 5x(x² - 3x - 1) + 10(x² - 3x - 1)

= 3x⁴ - 9x³ - 3x² + 5x³ - 15x² - 5x + 10x² - 30x - 10

= 3x⁴ - 4x³ - 8x² - 35x - 10

hence, expression of vanessa's patio = (3x⁴ - 4x³ - 8x² - 35x - 10)

b). 4320 have a nice day