Given: quadrilateral defg is a parallelogram. prove: gh ≅ eh dh ≅ fh proof: statement reason 1. quadrilateral defg is a parallelogram. given 2. definition of a parallelogram 3. draw and . these line segments are transversals cutting two pairs of parallel lines: and and and . drawing line segments 4. place point h where and intersect. defining a point 5. ∠hgd ≅ ∠hef ∠hdg ≅ ∠hfe 6. dg ≅ ef opposite sides of a parallelogram are congruent. 7. asa criterion for congruence 8. gh ≅ eh dh ≅ fh corresponding sides of congruent triangles are congruent. 1 what is the missing statement for step 7 in this proof? a. δdgh ≅ δfeh b. δghf ≅ δehd c. δdgf ≅ δfed d. δdef ≅ δedg

A.  ΔDGH ≅ ΔFEH

Step-by-step explanation:

We are given the proof of GH ≅ EH and DH ≅ FH.

Now, previous to step 7, we have obtained,

Step 5: ∠HGD ≅ ∠HEF  and ∠HDG ≅ ∠HFE

Step 6: DG ≅ EF as opposite sides of a parallelogram are congruent.

Since, we have that two angles of the triangles are congruent and their including sides are also congruent.

Thus, by Step 7 i.e. ASA criterion for congruence, we get that the corresponding triangles are also congruent.

Hence, we get, ΔDGH ≅ ΔFEH.

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

number one is the correct answer

step-by-step explanation: dogs and cats are mentioned, no other animals