Pranav made a nut mixture that contains 82% peanuts by mixing 6kg of mixed nuts with 9kg of peanuts. the mixed nuts contained what percent peanuts?

Ok so
82%=82/100=0.82

82% of all =peanuts

total=6+9=15kg

all=15
0.82 times 15=peanuts
12.3=peanuts

12.3kg of peanuts total
9kgpeanuts+xkgpeanuts(inmixednuts)=12.3
subtract 9 from both sides
xkgpeanuts=3.3kg

3.3/9=x%
x%=x/100
3.3/9=x/100
1.1/3=x/100
multiply both sides by 300
110=3x
divide both sides by 3
36.6666=x
36.6666% is answer
aprox 37%

Dis the correct answer