50 points! (i rlly need ) (algebra 1)

43.06 ft

3.20 seconds

Step-by-step explanation:

h = -16t^2 +50t +4

The maximum is at the vertex

The x coordinate for the vertex is a the axis of symmetry

The axis of symmetry is

h=-b/2a  when the equation is at^2 +bt+c

h = -50/2(-16)

   =-50/-32

   = 1.5625

The maximum is when x is at 1.5625

to find y we put this into the equation

h = -16(1.5623)^2 + 50(1.5625) +4

   = -16(2.44140625) + 78.125+4

   = -39.0625+78.125+4

   =43.0625

To the nearest hundredth

43.06 ft

The second part is to find when it hits the ground, or when h=0

0 = -16t^2 +50t +4

Using the quadratic formula

-b±sqrt(b^2 -4ac)

2a

-50±sqrt(50^2 -4*-16*4)

2*-16

-50±sqrt(2500 +256)

-32

-50±sqrt(2756)

-32

-50 + sqrt(2756)      or -50 + sqrt(2756)

-32                                          -32

-.078                                    3.20

Since time cannot be negative

3.20 seconds

option: d is the correct answer.

d) none of the above.

step-by-step explanation:

clearly from the figure attached to the question we could see that there is no shape given. hence without any shape given in the figure and after rotation we can't obtained a square pyramid.

since, to obtain a image we need a proper figure of the pre-image so that it can be transformed.

hence, the correct answer is:

d) none of the above.

step-by-step explanation: