In your notebook, set up the following subtraction in a vertical format and select the correct answer. reduce 7 y + 2 y2 - 7 by 3 - 4 y. 2 y2 - 11 y + 10 -2 y2 - 11 y + 10 -2 y2 + 11 y - 10 2 y2 + 11 y - 10

For every corresponding pair of cross sections, the area of the cross section of a sphere with radius r is equal to the area of the cross section of a cylinder with radius and height 2r minus the volume of two cones, each with a radius and height of r. a cross section of the sphere is and a cross section of the cylinder minus the cones, taken parallel to the base of cylinder, is the volume of the cylinder with radius r and height 2r is and the volume of each cone with radius r and height r is 1/3 pie r^3. so the volume of the cylinder minus the two cones is therefore, the volume of the cylinder is 4/3pie r^3 by cavalieri's principle. (fill in options are: r/2- r- 2r- an annulus- a circle -1/3pier^3- 2/3pier^3- 4/3pier^3- 5/3pier^3- 2pier^3- 4pier^3)

What type of symmetry does a rhombus have?

Write the equation of the line that passes through (3, 4) and (2, −1) in slope-intercept form. (2 points) y = 3x − 7 y = 3x − 5 y = 5x − 11 y = 5x − 9