He vertices of a triangle are p(-3,8), q(-6,-4), and r(1,1). name the vertices of the image reflected in the x-axis

P'(-3, -8), Q'(-6, 4), R'(1, -1)

Step-by-step explanation:

When you reflect a point (x, y) across the x-axis, the x-coordinate remains the same, but the y-coordinate gets the opposite sign: it becomes (x, -y).

Thus, if a point P, say, (-3, 8) is eightn units above the x-axis, its reflection P' will be the same distance below, at (-3, -8).

Thus, we get the following transformations.

P (-3, 8)   ⟶ P' (-3, -8)

Q (-6, -4) ⟶ Q' (-6, 4)

R (1, 1)      ⟶ R' (1, -1)

Thus, the vertices of the reflected triangle are P' (-3, -8), Q' (-6, 4), R' (1, -1).

The image below shows ∆PQR and its reflection ∆P'Q'R' across the x-axis.

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.

i did it myself and i got 4.2 (b) hope its right

step-by-step explanation: