For the function f(x) = (8-­2x)2 ,find f-­1 . determine whether f­-1 is a function. question 20 options: f­-1(x) = ±8+x2‾‾‾‾√ ± 8 + x 2 ; f­-1 is not a function f­-1(x) = ±8+x2‾‾‾‾√ ± 8 + x 2 ; f­-1 is a function f­-1(x) = 8±x√2 8 ± x 2 ; f­-1 is a function f­-1(x) = 8±x√2 8 ± x 2 ; f­-1 is not a function

Step-by-step explanation:

f(x)=(8-x)²

let y=f(x)

flip x and y

x=f(y)

f^{-1}x=y

y=(8-x)²

flip x and y

x=(8-y)²

±√x=8-y

y=8±√x

\[f^{-1}(x)=8±√x\]

it is not a function.

the perimeter is increased by a factor of 2

the answer is 0.3175 hope that you ^w^

also you might actually want to put this picture up if you want people to solve it luckily i remember this question