How many milliliters of olive oil (d=0.92 g/ml) have the same mass as 1.80 l of gasoline (d= .74 g/ml)

1448 mL

Step-by-step explanation:

The mass is the same.

Formula

m = d*V

Givens

Olive Oil

d = 0.92 grams / mL

V = ??

Gasoline

d = 0.74 grams / mL

V = 1.8 L = 1.8 L * (1000 ml / L)

V = 1800 mL

Solution

0.74 * 1800 mL = 0.92 * x                      Divide both sides by 0.92

0.74/0.92 * 1800 mL = 0.92 *x / 0.92   Combine the left

0.8043  * 1800 mL = x

x = 1448 mL

The volume of Olive Oil needed is 1448 mL

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.

b. hoped i'm right lol

step-by-step explanation: