Aperson is riding in a hot air balloon. for the first hour, the wind current is a constant 8.25 mph in the direction n37.5°e. then the wind current changes to 6.00 mph and heads the balloon in the direction s52.5°e. what is the bearing of the balloon from its starting point? round your answer to 1 decimal place.

The bearing of the balloon from its starting point = N 71.9° E

Step-by-step explanation:

To find the distance to the starting point, the wind and the height are perpendicular to each other. So, use the Pythagorean Theorem :

(Distance from the starting point)² = 8.25² + 6.00² = 112.56

⇒ Distance = 10.6 miles

Then to determine the bearing y :

Since the original bearing that the balloon set off at was N 37.5° E,  

⇒  y = 37.5° + 34.4°

       = 71.9°

Hence, The bearing of the balloon from its starting point = N 71.9° E

for finding the midpoint of any given 2 pair of points simply add the respective x coordinates with other x coordinate and the y coordinate with other y coordinate and divide them by 2

in your question it will be :

(3+1)/2 for the x coordinate of mid point i.e 2

[8+(-4)]/2 for the y coordinate of midpoint i.e 2

so coordinates of mid point of points (3,8) and (1,-4) will be (2,2)

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.