What is the factored form of the expression? 12g2 + g – 6

The factored form is 12g^2 + g – 6 = (3g-2)*(4g + 3).

Step-by-step explanation:

Given the expression is 12g^2 + g – 6.

the product of a*c = -72.

and the factors of b = +9 -8 = 1.

So, 12g^2 + g – 6 = 12g^2 + 9g - 8g - 6.

12g^2 + g – 6 = 3g*(4g + 3) -2*(4g + 3).

12g^2 + g – 6 = (3g-2)*(4g + 3).

Hence, the factored form is 12g^2 + g – 6 = (3g-2)*(4g + 3).

(4g+3)(3g-2)

Step-by-step explanation:

We have to make factored form of the expression.

Given expression is :

12g²+g-6

Split the middle term to make the equation into two groups such that the sum of 2 numbers should be 1 and their product be -72.

12g²+9g-8g-6

Making two groups and taking the common term out:

3g(4g+3)-2(4g+3)

Take (4g+3) common

(4g+3)(3g-2) which is factored form of 12g²+g-6.

b. x + 1

step-by-step explanation:

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c.

step-by-step explanation:

substitution for (0,1)

y=x^2+4x+1

1=0^2+4(x)0+1

1=0+4(x)0+1

1=4(x)0+1

1=0+1

1=1

substitution for (-3,-2)

y=x+1

-2=-3+1

-2=-2