F(x)=2x^2+3 and g(x)=x^2-7 find (f+g)(x)

3x^2 -4

Step-by-step explanation:

F(x)=2x^2+3 and g(x)=x^2-7

(f+g)(x) =

We add the two functions together

(f+g)(x) =2x^2+3+x^2-7

I like to line them up vertically

(f+g)(x) =

2x^2 +3

+x^2  -7

3x^2 -4

shift 4 units up, and 1 unit left.

it will translate f(x) = 3^x to g(x) = 3^(x+1) + 4

the answer is b: 18

step-by-step explanation:

use the pythagorean theorem to .

a^2+b^2=c^2

plug 18 for "r"

the 2 legs are 18 and 24

18^2+24^2=c^2

324+576=c^2

900=c^2

c=30

30-12=18

18 is the radius

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