The identity function i behaves just like the number 1. that is (f o i)=f and (i o g)= g it is also true that for a function k, (k o k^-1)=i use this information and algebra to solve h= (f o g) for f any insight would be !

I'll denote the identity function by . Then for any functions with inverse ,

One important fact is that composition is associative, meaning for functions , we have

So given

we can compose the functions on either side with :

then apply the rules listed above:

first one is a: renaming a fraction. second one is c: de-c

step-by-step explanation:

my explanation is that these were the answers on edg : )

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b