What is the argument of 3 - 3i? 300°315°330°345°

315

Step-by-step explanation:

z = a+bi

The modulus is the sqrt ( a^2 +b^2)

and the argument (I call it theta)  is equal to arctan (b/a)

We have z = 3-3i

We are looking for the argument of z

theta = arctan (-3/3)

           = -45 degrees

They don't like negative arguments so add 360 degrees to it.  It is the same value, we just loop once around the circle.

-45+360 =

315