The length of a rectangle is 5 times the width. if the perimeter is to be greater than 36 meters. what are the possible values for the width?

  The width must be greater than 3 meters.

Step-by-step explanation:

Let w represent the width. Then 5w will represent the length, which is 5 times the width. The perimeter is the total of the side lengths of the rectangle, so is ...

  P = 2w + 2(5w) = 12w

We want this to be greater than 36 m, so ...

  P > 36 m

  12w > 36 m . . . . . . . substitute our expression for P

  w > 3 m . . . . . . . . . . divide by 12

The possible values for width are those values that are more than 3 meters.

2. angles qrt and qst both measures 156 degrees.

step-by-step explanation:  

we have been given a diagram of a circle and we are told that measure of arc qvt is 156 degrees.  

we can see from our given diagram that angle qrt and angle qst subtends to arc qvt.

since we know that angles subtended by the same arc at the circumference are always equal.

by angle subtended by same arc theorem, measure of angle qrt and angle qst will be equal to the measure of arc qvt.

therefore, angles qrt and qst both measures 156 degrees and 2nd statement is the correct choice.

do you have a picture of the table