Pls what is the relative minimum of the function? enter your answer in the box

The relative minimum of the function is -2.

Step-by-step explanation:

We are given the graph of a parabola.

It is known that,

'The relative minimum is the least point on the graph where the graph changes its direction'.

Now, from the given graph, we have,

(-3,-2) is the minimum point of the function and also, at this point the graph is changing its direction.

Thus, the relative minimum of the function is at (-3,-2).

Since, in the ordered pair (x,y), the value 'y' represents the function value.

Hence, the relative minimum is -2.

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}