Ineed to know the answer to this algebra question.

x=2 is not a solution

Step-by-step explanation:

x^4 +2x^3 -x^2 -2x = 0

I will factor by grouping

x^4 -x^2  +   2x^3 -2x =0

Factor out x^2 from the first group and 2x from the second group

x^2(x^2-1) +2x(x^2-1) =0

Now factor out x^2-1

(x^2-1) (x^2+2x)=0

From the second term we can factor out an x

(x^2-1) x(x+2)=0

Using the zero product property

(x^2-1) =0     x = 0    (x+2)=0

x^2 =1             x=0          x=-2

Taking the square root

x=±1                x=0               x= -2

The solutions are -2,-1,0,1

the answer   is 200

step-by-step explanation:

this is a problem about poisson probabilities.   i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.  

here's how you can see a poisson distribution coming.   when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution.   this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot.   there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything.   the form of the distribution is

  probability of n chips = {[e^(-x)]*(x^n)} / (n! )

.632

step-by-step explanation:

6 * 1/10 = 3/5

3*0.01 = 0.03

3/5 + 0.03 = .63

2*0.002 = .002

.63 + 0.002 = .632