What are the solutions of the system? y = x^2 + 2x +3y = 4x - 2a. (-1, -6) and (-3, -14)b. (-1, 10) and (3, -6)c. no solutiond. (-1, -6) and (3, 10)

Option C. No solution is the right answer.

Step-by-step explanation:

Here the given equations are y = x²+2x+3 -----(1)

and y = 4x-2 -------(2)

Now we substitute the value of y from equation 2 into 1.

x²+2x+3 = 4x-2

x²+2x+3-2x = 4x-2-2x

x²+3 = 2x-2

x²+3-2x = 2x-2x-2

x²-2x+3 = -2

x²-2x+5 = 0

Then value of

Since in this solution √(-20) is not defined. Therefore there is no solution.

center= (-2,0)

radius= sqrt2/2

step-by-step explanation:

f(2x−x2)=−3x2+6x−1

step-by-step explanation:

set up the composite function and evaluate.

f(2x−x2)=−3x2+6x−1