At the beginning of the day, stock xyz opened at $6.12. at the end of the day, it closed at $6.88. what is the rate of change of stock xyz? a. 1.17% b. 11.0% c. 12.4% d. 81.5%

12.4%

Step-by-step explanation:

C is the correct option.

Step-by-step explanation:

We have been given that

stock XYZ opened at $6.12 and it closed at $6.88 and we have find the rate of change of stock.

Change in the value =| Initial - final |

Change in the value = |6.12-6.88|

Change in the value = 0.76

Hence, the rate of change of stock is given by

C is the correct option.

step-by-step explanation: you take each of the numbers and divide by the amount then you take the range

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this