Acoin is tossed twice. let e e be the event "the first toss shows heads" and f f the event "the second toss shows heads". (a) are the events e e and f f independent? input yes or no here: yes (b) find the probability of showing heads on both toss. input your answer here: preview

a.Yes, Event E and F are independent.

b.

Step-by-step explanation:

We are given that a coin is tossed twice.

S={HH,HT,TH,TT}

E={HH,HT}

F={HH,TH}

a.We have to find that event A and event B are independent or not.

We know that when two events A and B are independent then

Probability,P(E)=

Total number of cases=4

P(E)=

P(F)=

={HH}

Therefore, Event E and event B are  independent.

b.We have to find the probability of showing heads on both toss.

Number of favorable cases={HH}=1

Total number of cases=4

By using the formula of probability

The probability of getting heads on both toss=

the answer is 375 miles

step-by-step explanation:

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)