The ratio of bananas to strawberries in the drink is 4 to 12.what percent of the total fruit are bananas?

I believe that it is 48% or maybe 33.33%

Step-by-step explanation:

First off, I think you either take 12 and make it .12 and divide by 4 or do 4 divided by 12 and you get something like .333333333 cont. and times by 100 for both of the solutions

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;

yes   because as the functions are graphed they eventually will intersect unless otherwise

step-by-step explanation: