How many different triangles can you make with 14cm, 10cm and 50cm sides?

Hello from MrBillDoesMath!

0  (zero)

Discussion:

From the "triangle inequality", the sum of any two sides of a traingle must be greater than the length of the third side.  As 14 + 10 is not greater than (is less than) 50, o no such triangle exists

Thank you,

MrB

hello,

as we don't know if g(x) is continue,

answer b

f(x)=2x²-8x+1=2(x²-4x+4)+1-8=2(x-2)²-7

vertex is (2,-7) ( a minimum since coefficient of x² is > 0)