Pls if |7 − 6y| > 30, whats the possible value of y?

y<−23/6 or y> 37/6

Step-by-step explanation:

Solve Absolute Value.

|−6y+7|>30

We know either−6y+7>30or−6y+7<−30

−6y+7>30(Possibility 1)

−6y+7−7>30−7(Subtract 7 from both sides)

−6y>23

−6y /−6  > 23/−6

(Divide both sides by -6)

y<−23/6

−6y+7<−30(Possibility 2)

−6y+7−7<−30−7(Subtract 7 from both sides)

−6y<−37

−6y/−6< −37/−6

(Divide both sides by -6)

y> 37/6

Therefore the answer is

y<−23/6 or y> 37/6

I hope this helped you.

there is no question content here, but you for the free points! : d