Aworm is at the bottom of a 10ft hole. he starts climbing out of the hole, climbing 3 feet in one hour. then he takes a break for 1 hour and slides backward 1 foot. he repeats this pattern, climbing at a constant rate of 3 feet per hour and then sliding backward for an hour until he reaches the top. if the worm begins crawling at 9 am, what time will he reach the top of the hole.

6:00pm is the answer

Step-by-step explanation:

well there are two answers for that.

1: you need 120 ones then that will equal up to 120.

2: you could also do one 100 and 2 tens.

those are the answers that i have thought of.

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation: