In a tornado, the wind velocity in meters per second can be described by the function v(p)-12.3 1134 -3p where p is the air pressure in millibars. what is the air pressure of a tornado in which the wind velocity is 49.3 meters per second? round your answer to the nearest whole millibar.

In a tornado, the wind velocity in meters per second can be described by the function

 v(p)-12.3=1134 -3p

Whee,p=Pressure in Millibars

When, Wind Velocity =49.3 meters per second

We have to Calculate air Pressure.

49.3-12.3=1134-3p

37=1134-3p

3p=1134-37

3p=1097

So, Pressure=366 Millibar

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x = 17

step-by-step explanation:

in the given figure, two triangles are inscribed in a circle where ∠bae ≅ ∠dae which makes the side be and de equal so we can write it as:

3x - 24 = x + 10

solving this equation for x to get:

3x - x = 10 + 24

2x = 34

x = 34/2

x = 17

therefore, the value of x = 17.