25 ! what kind of problem is this and how do i solve it?asap

x^2-19x+48=

and how would you solve this one?

x^2+21x-100=

see explanation

Step-by-step explanation:

To solve the given quadratic equations, equate to zero, factorise and solve

given

x² - 19x + 48 = 0

Consider the factors of the constant term (+ 48) which sum to give the coefficient of the x- term (- 19)

The required factors are - 3 and - 16, hence

(x - 3)(x - 16) = 0

equate each factor to zero and solve for x

x - 3 = 0 ⇒ x = 3

x - 16 = 0 ⇒ x = 16

given

x² + 21x - 100 = 0

Consider the factors of the constant term (- 100) which sum to give the coefficient of the x- term (+ 21)

The required factors are + 25 and - 4, hence

(x + 25)(x - 4) = 0

x + 25 = 0 ⇒ x = - 25

x - 4 = 0 ⇒ x = 4

can you hlep me do homework?

step-by-step explanation: