(25 to the power of 9) + (5 to the power of 17) is divisble by 30.

prove the divisibility.

blank x 30

answer should be exponent with a base.

5^16

Step-by-step explanation:

25^9 + 5^17

Replace 25 with 5^2

5^2^9 + 5^17

We know that a^b^c = a^(b*c)

5^(2*9)+ 5^17

5^18+ 5^17

We can factor out 5^17

5^17 (5+1)

5^17(6)

But we need 30 so I need one more 5 inside 5^17 = 5^16 *5

5^16 *5 *6

5^16(30)

b

2

−

b

b

3

+

7

b

2

+

14

b

+

6

%

−

3

b

3

+

7

b

2

+

14

b

+

6

%

step-by-step explanation: