If α and β are the zeros of the polynomials 3y²-8 y + 4, find a quadratic polynomial whose roots are 1/α and 1/β

4y² - 8y + 3 = 0

Step-by-step explanation:

given 3y² - 8y + 4 ← in standard form

with a = 3, b = - 8, c = 4

and that α and β are roots of the polynomial, then

α + β = - = , and

αβ = =

sum of new roots = +

                             =

                             = = 2

product of new roots =  ×

                                   = = =

Hence the required equation is

y² - 2y + = 0 ( multiply through by 4 )

4y² - 8y + 3 = 0

answear:

a

step-by-step explanation: a

b

step-by-step explanation:

it have 5 sides and 5 identicle angle.the rest does not have the same property as b.

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