In the equation ( ax+3)²=36, a is a constant. if x = -3 is one solution to the equation, what is a possible value of a?

a = -1 or 3

Step-by-step explanation:

( ax+3)²=36

We will let x =-3

( -3a+3)²=36

Take the square root of each side

sqrt( ( -3a+3)²)=±sqrt(36)

( -3a+3)=±6

-3a +3  = 6                     -3a+3 = -6

Subtract 3 from each side

-3a +3-3 = 6-3               -3a+3-3 = -6-3

-3a = 3                            -3a =-9

Divide by -3

-3a/-3 = 3/-3                     -3a/-3 = -9/-3

a = -1                                        a =3

a can be either -1 or 3

i think there was a typo. you wrote pat brings 3 quarts of ice-cream to the party. each serving of ice-cream is 1 6 quart. how many total servings of ice-cream does pat bring to the party? i think the bold is supposed to be 1/6. so 1 quart of ice cream = 6 servings. 6 * 3 = 18.