Aline has a slope of 8/9. a second line that passes through points (-6,-3) and (-3,5). would these be parallel , perpendicular or neither ?

Let's find the slope of the line through the two given points. Use the slope formula

m = (y2 - y1)/(x2 - x1)

m = (5 - (-3))/(-3 - (-6))

m = (5 + 3)/(-3 + 6)

m = 8/3

The slope of the line through the two points is 8/3. This is not equal to the other slope of 8/9, so the two lines are not parallel.

Multiply the two slopes together. If you get -1, then the lines are perpendicular.

(slope1)*(slope2) = (8/9)*(8/3) = (8*8)/(9*3) = 64/27 = 2.37 approximately

The result is not -1, so the lines are not perpendicular.

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step-by-step explanation:

x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17