The sum of two consecutive integers is 77 find the integers

Hello from MrBillDoesMath!

38,39

Discussion:

Call the first integer "n". Then

n + ( n+1) = 77                 =>

2n + 1      = 77                 => subtract 1 from both sides

2n            = 77 - 1 = 76   => divide both sides by 2

n = 76/2 = 38

The first integer is n = 38 and the next consecutive one (= n+1) is 38 + 1 = 39.  Finally, 38 + 39 = 77

Thank you,

MrB

(3x-8) or (3x+8)

step-by-step explanation:

22.83 repeating

step-by-step explanation:

137 ÷ 6 is 22.8333333 therefore we understand that 3 is repeating.

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