Somebody pls answer

write the first four terms of the function f(n)=n^2-1

0,3,8,15

Step-by-step explanation:

f(n)=n^2-1

The first term is

f(1) = 1^2 -1 = 1-1 =0

The second terms is

f(2) = 2^2 -1 = 4-1 = 3

The third term is

f(3) = 3^2 -1 = 9-1 =8

The fourth term is

f(4) = 4^2 -1 = 16-1 =15

y < -3

step-by-step explanation:

-3y - 2 > 7

-3y -2 + 2 > 7+2

-3y > 9

-3y/-3 < 9/-3   (change the inequality sign when multiplying or dividing by a negative number)

y < -3

your answer is the frist one

hop i