Acertain genetic condition affects 8% of the population in a city of 10,000. suppose there is a test for the condition that has an error rate of 1% (i. e., 1% false negatives and 1% false positives).

consider the values that would complete the table below.

has condition does not have condition totals

test positive

test negative

totals

what is the probability (as a percentage) that a person has the condition if he or she tests positive? (round your answer to one decimal place.)

Let be the event that a randomly selected person has the condition, and the event that the test returns a positive result. We are given that

(false positive; that is, the event that the test incorrectly returns a positive result)

(false negative; incorrectly returns a negative result)

We want to find . By definition of conditional probability,

By the same definition,

and by the law of total probability,

So we have (and this is known as Bayes' rule)

step-by-step explanation:

(a) common ratio in the given sequence is, 3

(b) push ups will do kendall do on the 20th week

step-by-step explanation:

geometric sequence is a sequence of numbers that follows a pattern were the next term is found by multiplying by a constant called the common ratio(r)

(a)

given the sequence: 6 , 18 , 54 , 162 ,

this sequence is geometric sequence where each term is 3 times the previous term.

therefore,

common ratio(r) = 3.

(b)

a formula for nth term of geometric sequence is given by;

,   where r is the common ratio between the successive terms and is the first term,

to find how many push ups will kendall do on the 20th week.

here. n = 20th term.

in the given sequence first term

then;

simplify:

therefore, push ups will do kendall do on the 20th week