What are the zeros of the function f(x)=(x+16)(2x-3)(3x+4)

see explanation

Step-by-step explanation:

given f(x) in factored form, set f(x) = 0 and solve, that is

(x + 16)(2x - 3)(3x + 4) = 0

Equate each factor to zero and solve for x

x + 16 = 0 ⇒ x = - 16

2x - 3 = 0 ⇒ 2x = 3 ⇒ x =

3x + 4 = 0 ⇒ 3x = - 4 ⇒ x = -

The zeroes are

x = - 16, x = , x = -

b) 1/3 * 1/5

step-by-step explanation:

each smallest part is 1/15 since the written one is 1/5 and it's divided by 3 equal parts. (1/5 )/3 = 1/15 = 1/3 * 1/5