What is the sum of an infinite geometric series if the first term is 156 and the common ratio is 2⁄3? a. 260 b. 468 c. 234 d. 208

S = a0 / (1 - r)

S is the sum

a0 is the first term

r is the ration

The sum is 2, and the first term is 0.5, so plug in what you know and see what you come up with:

2 = 0.5 / (1 - r)

That's an equation you can solve:

2(1 - r) = 0.5

1 - r = 0.5 / 2 = 0.25

0.75 - r = 0

0.75 = r

Ratio is 0.75.

i think it's ф or x=6,-6

step-by-step explanation:

-x^2=-36

x^2=-36

ф

or

if you mean by : -(x^2)=-36

it'll be: x^2=36

x=6,x=-6

hope it'll ! have a good day!

you for asking!

1. d.90

2. e. none of these (80)

3. a. 0

4. b. 6

5. e. none of these (10)

6. a. 5