Prove that the sum of two consecutive exponents of the number 6 is divisible by 7.

Step-by-step explanation:

To prove: The sum of two consecutive exponents of the number 6 is divisible by 7.

Proof: Let the consecutive exponents of the number 6 be:

and .

Then , the sum of two consecutive exponents of the number 6 is represented as :

.

Now, according to question, we have to prove that The sum of two consecutive exponents of the number 6 is divisible by 7, thus

=

⇒=

which means that the sum of two consecutive exponents of the number 6 is divisible by 7.

Hence proved.

answer: a. 74

step-by-step explanation:

it shows divided evenly, so add the 37+37 = 74

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