Triangles abc and def. coordinates for a are 0, 1, for b 0, 2, and for c 3, 2. given: δabc ≅ δedf what is the length of segment line fe rounded to the nearest tenth? 3 4 1.1 3.2 you must check the box below prior to submitting your exam! check this box to indicate you are ready to submit your exam explorer toolbox workload my folders current course: instructors monitor all areas of a student's account student e-mail accounts are to be used for flvs course-related email only and not for general introductions or spamming of people in your address book. remember to click the logoff link when you have completed your work in the course. fdk361.02

3.2 units

Step-by-step explanation:

We are given that triangle ABC and triangle DEF are congruence.

The triangle ABC with coordinates A (0,1),B(0,2) and C(3,2).

We have to calculate the length of segment line EF round to nearest tenth.

Given

Therefore, we have AB=ED,BC=DF and AC=EF

Using distance formula

Length of AC=

Length of AC= units

Length of AC=Length of EF=3.2 units

Hence, the length of segment line EF is 3.2 units

51

step-by-step explanation:

73-22=51 the   mass number minus the amount of protons gives you the amount of neutrons

to find the perimeter of the rectangle this is the expression:

x-9+x-9+3x-4+3x-4=138

if we simplify it:

8x-26=138

remember, 138 is what it all adds up to

the length is 11.5cm

the width is 57.5cm

the area is 661.25cm^2

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