Asap 25 pts + braianliest to right/best answer

Replace f(x) with y:

y = x^2 -1

swap the variables:

x = y^2 -1

Solve for y:

Add 1 to each side:

y^2 = x+1

Take the square root of both sides:

y = √(x+1)

To complete the solution use both the positive and negative values.

f^-1(x) = +/+√(x+1)

The last answer is the right one.

f^-1(x) = ±sqrt(x+1)

Step-by-step explanation:

f(x) = x^2 -1

To find the inverse, exchange x and y and then solve for y

y = x^2 -1

Exchange x and y

x = y^2 -1

Add 1 to each side

x+1 = y^2

Take the square root of each side

±sqrt(x+1) = sqrt(y^2)

±sqrt(x+1) = y

f^-1(x) = ±sqrt(x+1)

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.

where is abdul's work? don't see that anywhere posted : /

step-by-step explanation: