100 points (urgent)
the school that stephen goes to is selling tickets to a choral performance. on the first day of tickets sales the school sold 3 senior citizen tickets and 1 child ticket for a total of 38$ the school took in 52$ on the second by selling 3 senior citizen tickets band 2 child tickets. find the price of a senior citizen ticket and the price of a child ticket

Let the price of a senior ticket = x and a child ticket = y

Day 1 you have 3x + 1y = 38

Day 2 you have 3X + 2Y = 52

Using the subtraction method:

3x - 3x = 0

2y - 1y = 1y

52 - 38 = 14

So you have 1y = 14, which means the price of a child ticket is 14.

Using day 1 now you have 3x +1(14) = 38

Simplify:

3x + 14 = 38

Subtract 14 from each side:

3x = 24

Divide both sides by 3:

x = 24 /3 = 8

Senior tickets cost $8 and child tickets cost $14

if im undersanding the question correctly, its organized from 10

step-by-step explanation:

i believe it is c.y = 9x

rise over run. 9 units up over 1 unit right or 9/1