In the lab, debra has two solutions that contain alcohol and is mixing them with each other. solution a is 10% alcohol and solution b is 50% 2400 milliliters of solution a. how many milliliters of solution b does she use, if the resulting mixture is a 20% alcohol solution?

  800 mL

Step-by-step explanation:

Let b represent the amount of solution B added to 2400 mL of solution A. The total amount of alcohol (mL) in the mixture is ...

  10%×2400 + 50%×b = 20%×(2400 +b)

multiplying by 100 to get rid of the % signs and simplifying, we have ...

  24000 +50b = 48000 +20b

  30b = 24000 . . . . . . . . . subtract 24000+20b

  b = 800 . . . . . . . . . . . . . . divide by 30

Debra added 800 mL of 50% alcohol to her 2400 mL of 10% alcohol to make a 20% solution.

b

2

−

b

b

3

+

7

b

2

+

14

b

+

6

%

−

3

b

3

+

7

b

2

+

14

b

+

6

%

step-by-step explanation:

step-by-step explanation:

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