The point (5,-6) lies on a circle and the center of the circle is at the point (5,-8).
what is the equation of this circle?
a.
(x - 5)2 + (y + 8)2 = 4
b.
(x - 8)2 + (y - 5)2 = 4
c.
(x + 5)2 + (y - 8)2 = 4
d.
(x - 8)2 - (y - 5)2 = 2

A.  

(x - 5)^2 + (y + 8)^2 = 4

Step-by-step explanation:

The equation for a circle in center radius form is

(x-h)^2 + (y-k)^2 = r^2  where (h,k) is the center and r is the radius

We need to determine the radius, from the two points which is the distance

d = sqrt( (x2-x1)^2 + (y2-y1)^2)

  = sqrt( (5-5)^2+( -8--6)^2)

  = sqrt(0+ (-8+6)^2)

  = sqrt( 0+(-2)^2)

  = sqrt(4)

  = 2

The radius is 2 and the center is (5,-8)

(x-5)^2 + (y--8)^2 = 2^2

(x-5)^2 + (y+8)^2 = 4

1. 3.4/4

2. 0.8/7

3. 0.5 x 3

4. 0.9 x 6

5. 10.8

6. 2.35

7. 0.567

8. 9.35

9. 0.02

10. 0.06

11. 0.16

12. 0.42

13. 0.63

14. 5.6

15. 8.1

16. 9.9

17. 0.28

18. 0.48

19. 0.27

20. 0.49

21. 0.45

22. 0.72

23. 0.9

24. 0.88

25. 0.75

26. 0.16

27. 0.328

28. 0.495

29. 0.72

30. 1.068

answer: 193

explanation:

200-7 = 193