In a certain algebra 2 class of 24 students, 8 of them play basketball and 15 of them play baseball. there are 7 students who play neither sport. what is the probability that a student chosen randomly from the class plays both basketball and baseball?

Using the rules of probability:

P(A∩B)=P(A)+P(B)−P(A∪B) = 8/24 + 15/24 − 17/24 = 6/24 which reduces to 1/4 Play both.

10/60

step-by-step explanation:

if you divide 10 by 60 the answer is 0.166666 while if you divide or solve the other problems it equals 0.6