Astore manager is ordering shirts for $5 each and pants for $8 each. she buys a total of 80 items at a cost of $430. the system of equations {x+y=805x+8y=430 can be used to solve for the number of shirts, x, and the number of pairs of pants, y, the manager orders.

what is the solution?

Given the equaiton system, we can use the method of solving two equations to find the

x+y=80

5x+8y=430

Break it down into two equaitons:

x+y = 80

y = 80 - x ...(1)

5x + 8y = 430...(2)

We can then use the method of substitution to find the answers:

Put (1) into (2),

5x + 8(80-x) = 430
5x + 640 - 8x = 430
-3x = 430 - 640
-3x = -210
x = 210/3
x = 70...(3)

Now thay we find x, we can put it into the first eqaution to find y:

x+y = 80
70+y = 80
y = 10

Therefore, x= 70 and y = 10.

Hope it helps!